domingo, 22 de mayo de 2011

semana 10

Encontrar todos los elementos de un triangulo oblicuángulo y su superficie.


a=36                                A+B+C=180°                                    FORMULA GENERAL

b=28.47                          70°+48°+C=180°                              Sen A = sen B = sen C

c=54.07                           118°+C=180°                                        a            b         c

A=36°                              C=180°-118

B=48°                              C=62°

C=62°


S=452.34us²

Formula                                        sustitución

Sen A = sen B                           Sen 70° = sen 48°

     a           b                                   36              b

Resultado

b=sen48°(36)÷sen70°= 28.47



Formula                                             sustitución

Sen A = sen C                               Sen 70° = sen 62°

    a           c                                         36            c



Resultado

c=sen62°(36)÷sen70°= 33.82

Superficie

Formula                                sustitución

senØ= c.o                            sen 62°= h               sen 62°(28.47)=h             h=25.13

            H                                         28.47

bxh÷2                                     36x25.13=452.34us²


Encontrar todos los elementos de un triangulo oblicuángulo y su superficie.

a=16.5cm                                    A+B+C=180°                         FORMULA GENERAL

b=13.54cm                                  A+47°+70°=180°                   Sen A = sen B = sen C

c=17.40cm                                   A+117°=180°                            a            b          c

A=63°                                          A=180°-117

B=47°                                          C=63°

C=70°

S=104.922us²

Formula                              sustitución

Sen A = sen B                     Sen 63° = sen 47°

    a            b                       16.5cm           b

Resultado

b=sen47°(16.5cm)÷sen63°= 13.54cm



Formula                                  sustitución

Sen A = sen C                        Sen 63° = sen 70°

     a         c                                16.5           c



Resultado

c=sen70°(16.5)÷sen63°= 17.40cm

Superficie

Formula sustitución

senØ= c.o                             sen 63°= h                sen 63°(13.54)=h                  h=12.06

            H                                          13.54

bxh÷2                                     17.40x12.06=104.922us²

Encontrar todos los elementos de un triangulo oblicuángulo y su superficie.


a=46.24cm                               A+B+C=180°                     FORMULA GENERAL

b=154.10cm                             70°+48°+C=180°                Sen A = sen B = sen C

c=157cm                                   118°+C=180°                         a           b           c

A=17°                                       C=180°-118

B=77°                                       C=62°

C=83°

S=205,647.45us²

Formula                                   sustitución

Sen A = sen  C                     Sen 17° = sen 83°

     a            c                             a             157cm

Resultado

a=sen17°(157cm)÷sen83°= 46.24cm



Formula                                      sustitución

Sen A = sen B                            Sen 17° = sen 77°

     a          b                                  46.24         c



Resultado

b=sen77°(46.24)÷sen17°= 154.1cm

Superficie

Formula sustitución

senÅØ= c.o              sen 62°= h              sen 17°(154.10)=h                h=2619.7cm

             H                            154.10cm

bxh÷2                          157x2619.7=205,646.45us²

Encontrar todos los elementos de un triangulo oblicuángulo y su superficie.


a=85.87cm                        A+B+C=180°                 FORMULA GENERAL

b=90cm                            70°+B+30°=180°             Sen A = sen B = sen C

c=45.69cm                        100°+B=180°                      a            b          c

A=70°                                B=180°-100

B=80°                               B=80°

C=30°

S=452.34us²

Formula                                  sustitución

Sen A = sen B                     Sen 70° = sen 80°

   a           b                                a            90

Resultado

b=sen70°(90)÷sen80°= 85.87cm



Formula sustitución

Sen A = sen C                    Sen 70° = sen 30°

     a           c                       85.87cm        c



Resultado

c=sen30°(85.87cm)÷sen70°= 45.69cm

Superficie

Formula                         sustitución

senÅØ= c.o                   sen 30°= h                 sen 30°(85.87)=h               h=25.10cm

               H                               85.87cm

bxh÷2                         90x25.10=1129.5us²

Encontrar todos los elementos de un triangulo oblicuángulo y su superficie.


a=21cm                             A+B+C=180°                       FORMULA GENERAL

b=15.47cm                        70°+48°+C=180°                  Sen A = sen B = sen C

c=16.20cm                        118°+C=180°                             a            b         c

A=83°                                C=180°-118

B=47°                                 C=62°

C=50°

S=124.425us²

Formula                           sustitución

Sen A = sen B                  Sen 83° = sen 47°

   a           b                        21cm            b

Resultado

b=sen47°(21cm)÷sen83°= 15.47cm



Formula                                sustitución

Sen A = sen C                       Sen 83° = sen 50°

  a            c                              21cm            c



Resultado

c=sen50°(21cm)÷sen83°= 16.20cm

Superficie

Formula sustitución

senÅØ= c.o                        sen 62°= h               sen 62°(15.47)=h               h=11.85cm

               H                                      15.47

bxh÷2                                  21x11.85=124.425us²

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