domingo, 13 de febrero de 2011

Circunferencia fuera del origen

Encontrar la ecueación de la circunferenca en su forma ordinaria y general.

c(5,2)    r=6

(x-h)² + (y-k)²=r²


(x-5)² + (y-2)²=6²

(x-5)² + (y-2)²=36         forma Ordinaria




x²-10x+25+y²-4y+4=36

x²+y²-10x - 4y+29-36=0

x²+y²-10x - 4y-7=0         forma General
c(-3,-6)   r=5
(x-h)² + (y-k)²=r²

(x+3)² + (y+6)²=5²

(x+3)² + (y+6)²=25              forma Ordinaria




x²+6x+9+y²+12y+36=25

x²+y²+6x +12y+45-25=0

x²+y²+6x +12y+20=0           forma General
                   
c(3,-2)   r=4

(x-h)² + (y-k)²=r²

(x-3)² + (y+2)²=4²

(x-3)² + (y+2)²=16           forma Ordinaria





x²-6x+9+y²+4y+4=16

x²+y²-6x+ 4y+13-16=0

x²+y²-6x +4y-3=0       forma General



c(5,5)   r=2

(x-h)² + (y-k)²=r²

(x-5)² + (y-5)²=2²

(x-5)² + (y-5)²=4             forma Ordinaria





x²-10x+25+y²-10y+25=36

x²+y²-10x – 10y+50-4=0

x²+y²-10x - 10y-46=0               forma General



c(-2,-3)   r=10

(x-h)² + (y-k)²=r²

(x+2)² + (y+7)²=10²

(x+2)² + (y+7)²=100                 forma Ordinaria





x²-4x+4+y²+14y+49=100

x²+y²+4x +14y+53-100=0

x²+y²+4x+14y-47=0               forma General



c(-5,-8)   r=2


(x-h)² + (y-k)²=r²

(x+5)² + (y+8)²=2²

(x+5)² + (y+8)²=4              forma Ordinaria





x²+10x+25+y²+16y+64=4

x²+y²+10x +16y+89-4=0

x²+y²+10x+16y+85=0                   forma General








c(-2,6)   r=3

(x-h)² + (y-k)²=r²

(x+2)² + (y-6)²=3²

(x+2)² + (y-6)²=9             forma Ordinaria





x²+4x+4+y²-12y-36=9

x²+y²+4x -12y-8-9=0

x²+y²+4x-12y-18=0                   forma General



c(-2,0)   r=4

(x-h)² + (y-k)²=r²

(x+2)² + (y-0)²=4²

(x+2)² + (y-0)²=4             forma Ordinaria





x²+4x+4+y²-y-0=16

x²+y²+4x –y+4-16=0

x²+y²+4x-y-12=0           forma General











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